Respuesta :
Hello !
Here are some rules for logarithms : log ₐ b = n ⇔ aⁿ = b
log ₐ aⁿ = n
log ₐ (b·c) = logₐ b + log ₐ c
log ₐ bⁿ = n· log ₐ b ____________________________________________________
25=5²
625=5⁴
100 = 5² · 2²
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(log₅ 25 + log₅ 625) / log₅100 =
(log₅ 5²+ log₅ 5⁴) / log₅ (5² · 2²) =
(log₅ 5²+ log₅ 5⁴) /( log₅ 5² + log₅ 2²) =
(2 + 4)/(2+log₅ 2² ) =
6/ (2+2·log₅2)=
6/2 + 6/ (2·log₅2) =
3+ 3/log₅2
log₅2 = 0.5
So 3+ 3/log₅2 = 3 + 3/0.5 =3 + 6 = 9
Answer : 9
Here are some rules for logarithms : log ₐ b = n ⇔ aⁿ = b
log ₐ aⁿ = n
log ₐ (b·c) = logₐ b + log ₐ c
log ₐ bⁿ = n· log ₐ b ____________________________________________________
25=5²
625=5⁴
100 = 5² · 2²
____________________________________________________
(log₅ 25 + log₅ 625) / log₅100 =
(log₅ 5²+ log₅ 5⁴) / log₅ (5² · 2²) =
(log₅ 5²+ log₅ 5⁴) /( log₅ 5² + log₅ 2²) =
(2 + 4)/(2+log₅ 2² ) =
6/ (2+2·log₅2)=
6/2 + 6/ (2·log₅2) =
3+ 3/log₅2
log₅2 = 0.5
So 3+ 3/log₅2 = 3 + 3/0.5 =3 + 6 = 9
Answer : 9