A line passes throughout (-3,-2) and is perpendicular to 3x-2y=7. What is the equation of the line in slope-intercept form? A. Y=3/2X B. Y=3/2x+4 C. y=-2/3x-4 D. y=/2/3x
3x - 2y = 7 -2y = -3x + 7 y = 3/2x - 7/2....slope of this line is 3/2. A perpendicular line will have a negative reciprocal slope. All that means is " flip " the slope and change the sign. So the slope we need is -2/3 (see how I flipped the slope and changed the sign)
y = mx + b slope(m) = -2/3 (-3,-2).....x = -3 and y = -2 now we sub and find b, the y int -2 = -2/3(-3) = b -2 = 2 + b -2 - 2 = b -4 = b
so ur perpendicular equation is : y = -2/3x - 4 <==
