kimbers
kimbers
03-06-2015
Mathematics
contestada
x^2-8x+5=0 Solve by completing the square.
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konrad509
konrad509
03-06-2015
[tex]x^2-8x+5=0 \\ x^2-8x+16-11=0\\ (x-4)^2=11\\ x-4=-\sqrt{11} \vee x-4=\sqrt{11}\\ x=4-\sqrt{11} \vee x=4+\sqrt{11}\\[/tex]
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Please help! :) Solve for x to the nearest tenth. X^2+x-5=0
